# Polar decomposition

The positive-semidefinite matrix *P* is always unique, even if *A* is singular, and is denoted as

This is known as the left polar decomposition, whereas the previous decomposition is known as the right polar decomposition. Left polar decomposition is also known as reverse polar decomposition.

The core idea behind the construction of the polar decomposition is similar to that used to compute the singular-value decomposition.

Note how, from the above construction, it follows that .

*the unitary matrix in the polar decomposition of an invertible matrix is uniquely defined*

The **polar decomposition** of any bounded linear operator *A* between complex Hilbert spaces is a canonical factorization as the product of a partial isometry and a non-negative operator.

The polar decomposition for matrices generalizes as follows: if *A* is a bounded linear operator then there is a unique factorization of *A* as a product *A* = *UP* where *U* is a partial isometry, *P* is a non-negative self-adjoint operator and the initial space of *U* is the closure of the range of *P*.

The existence of a polar decomposition is a consequence of Douglas' lemma:

The operator *C* can be defined by *C(Bh)* := *Ah* for all *h* in *H*, extended by continuity to the closure of *Ran*(*B*), and by zero on the orthogonal complement to all of *H*. The lemma then follows since *A ^{*}A* ≤

*B*implies

^{*}B*Ker*(

*B*) ⊂

*Ker*(

*A*).

In particular. If *A ^{*}A* =

*B*, then

^{*}B*C*is a partial isometry, which is unique if

*Ker*(

*B*) ⊂

^{*}*Ker*(

*C*). In general, for any bounded operator

*A*,

where (*A ^{*}A*)

^{½}is the unique positive square root of

*A*given by the usual functional calculus. So by the lemma, we have

^{*}Afor some partial isometry *U*, which is unique if *Ker*(*A ^{*}*) ⊂

*Ker*(

*U*). Take

*P*to be (

*A*)

^{*}A^{½}and one obtains the polar decomposition

*A*=

*UP*. Notice that an analogous argument can be used to show

*A = P'U'*, where

*P'*is positive and

*U'*a partial isometry.

When *H* is finite-dimensional, *U* can be extended to a unitary operator; this is not true in general (see example above). Alternatively, the polar decomposition can be shown using the operator version of singular value decomposition.

By property of the continuous functional calculus, *|A|* is in the C*-algebra generated by *A*. A similar but weaker statement holds for the partial isometry: *U* is in the von Neumann algebra generated by *A*. If *A* is invertible, the polar part *U* will be in the C*-algebra as well.

If *A* is a closed, densely defined unbounded operator between complex Hilbert spaces then it still has a (unique) **polar decomposition**

where |*A*| is a (possibly unbounded) non-negative self adjoint operator with the same domain as *A*, and *U* is a partial isometry vanishing on the orthogonal complement of the range *Ran*(|*A*|).

The proof uses the same lemma as above, which goes through for unbounded operators in general. If *Dom*(*A ^{*}A*) =

*Dom*(

*B*) and

^{*}B*A*=

^{*}Ah*B*for all

^{*}Bh*h*∈

*Dom*(

*A*), then there exists a partial isometry

^{*}A*U*such that

*A*=

*UB*.

*U*is unique if

*Ran*(

*B*)

^{⊥}⊂

*Ker*(

*U*). The operator

*A*being closed and densely defined ensures that the operator

*A*is self-adjoint (with dense domain) and therefore allows one to define (

^{*}A*A*)

^{*}A^{½}. Applying the lemma gives polar decomposition.

If an unbounded operator *A* is affiliated to a von Neumann algebra **M**, and *A* = *UP* is its polar decomposition, then *U* is in **M** and so is the spectral projection of *P*, 1_{B}(*P*), for any Borel set *B* in [0, ∞).

In the Cartesian plane, alternative planar ring decompositions arise as follows:

The combination of inversion and Hermite conjugation is chosen so that in the singular value decomposition, the unitary factors remain the same and the iteration reduces to Heron's method on the singular values.